WebJul 4, 2024 · In an APa n=4, d=2, S n= 14,find n and a Byju's Answer Standard X Mathematics Arithmetic Progression In an APa n=4... Question In an AP an=4 , d=2, Sn =-14 ,find n and … WebThe students of a school decided to beautify the school on the Annual Day by fixing colourful flags on the straight passage of the school. They have 2 7 flags to be fixed at intervals of every 2 m. The flags are stored at the position of the middle most flag. Ruchi was given the responsibility of placing the flags.
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WebDec 30, 2016 · Math Secondary School answered • expert verified In an AP, an = 4, d = 2, Sn = -14 find n and a. See answers Advertisement ARoy =a+ (n-1)d=4 or, a+ (n-1)2=4 or, a+2n … WebAug 26, 2024 · The sum of the first n terms of an AP is given by Sn, = 3n^2 - 4n. Determine the AP and the 12th term. asked Feb 1, 2024 in Mathematics by Kundan kumar ( 51.5k points)
WebMay 5, 2024 · In an AP if a=50, d= -4 , and Sn=0 , then find the value of n Get the answers you need, now! deyrama17gmailcom deyrama17gmailcom 05.05.2024 Math Secondary School answered • expert verified In an AP if a=50, d= -4 , and Sn=0 , then find the value of n See answers Advertisement Web(viii) Given an=4, d=2, Sn=−14, find n and a. (ix) Given a=3,n=8,S=192, find d. (x) Given l=28,S=144, and there are total 9 terms. Find a. Q. In an AP (i) Given a =5,d=3,an=50, find n and Sn. (ii) Given a=7,a13=35, find d and S13. (iii) Given a12=37,d=3, find a and S12. (iv) Given a3 =15,S10 =125, find d and a10. (v) Given d=5,S9=75, find a and a9.
WebThe sum of n terms of an AP can be easily found out using a simple formula which says that, if we have an AP whose first term is a and the common difference is d, then the formula of the sum of n terms of the AP is S n = … WebMar 29, 2024 · Given a = 2, d = 8, Sn = 90 We can use formula Sn = 𝑛/2 (2𝑎+ (𝑛−1)𝑑) Putting a = 2, d = 8, Sn = 90 90 = 𝑛/2 (2 × 2+ (𝑛−1) × 8) 90 = 𝑛/2 (4+8𝑛−8) 90 × 2 =𝑛 (4+8𝑛−8) 180 = n (8n – 4) 180 = 8n2 – 4n –180 + 8n2 – 4n = 0 8n2 – 4n – 180 = 0 8n2 – 4n – 180 = 0 4 (2n2 – n – 45) = 0 2n2 – n – 45 = 0 2n2 – 10n + 9n – 45 = 0 2n (n – 5) + 9 (n – 5) = 0 (2n + …
WebMar 28, 2024 · Given an = 4, d = 2, Sn = –14 Since there are n terms, 𝑙 = an = 4 We use the formula Sn = 𝒏/𝟐 (𝒂+𝒍) Putting Sn = −14, 𝑙 = an = 4 –14 = 𝑛/2 (𝑎+4) –14 × 2 =𝑛 (𝑎+4) –28 = n (a + 4) …
Web- YouTube #arithematic_progressions given an AP. a = 4, d = 2, Sn = –14, find n and a. Ashokanan eduhub 184 subscribers Subscribe 0 Share Save No views 1 minute ago... date dimension script with fiscal yearWebJun 24, 2024 · Chapter-5 ARITHMETIC PROGRESSION Exercise-5.3 Question-3In an AP: (viii) given an = 4, d = 2, Sn = –14, find n and a bivalent covid vaccine washington stateWebOct 25, 2024 · In an AP: (i) given a = 5, d = 3, an = 50, find n and Sn. (ii) given a = 7, a13 = 35, find d and S13. (iii) given a12 = 37, d = 3, find a and S12. (iv) given a3 = 15, S10 = 125, find d and a10. (v) given d = 5, S9 = 75, find a and a9 (vi) given a = 2, d = 8, Sn = 90, find n and an (vii) given a = 8, an = 62, Sn = 210, find n and d. (viii) given ... bivalent covid vaccine for kidsWebS₂ = sum of first two terms of an AP = a+ a + d = 2a + d To find the common difference d, 2a + d = 18 2 (5) + d = 18 10 + d = 18 d = 18 - 10 d = 8 The series can be framed as a = 5 a + d … bivalent covid vaccine information sheetWebMay 5, 2024 · Solution: We have, a = 50, d=-4 and S n = 0 We know that S n = n/2 [2a+ (n−1)d] 0 = n/2 [2.50+ (n−1) (-4)] 0 = n/2 [100+ (-4n+4)] 0 = n/2 (104-4n) 4n = 104 n = 104/4 n = 26 Related questions 0 votes 1 answer If an AP is Sn = n (4n+1), then find the AP asked May 5, 2024 in Class X Maths by kabita (13.8k points) class-10 0 votes 1 answer bivalente showerWebIn an AP, given a=8,a n=62,S n=210m find n and d. Easy Solution Verified by Toppr a=8,a n=62,s n=210 a n=a+(n−1)d 62=8+(n−1)d 54=(n−1)d s n= 2n[2a+(n−1)d] 210= 2n[16+(n−1)d] 420=n[16+54] 420=70n n=6 54=(6−1)d d= 554 Was this answer helpful? 0 0 Similar questions In an AP, given a =2, d =8, S n=90, find n and a n. Easy View solution > bivalent eua fact sheetWebSolution Given that, an = 4, d = 2, Sn = −14 an = a + ( n − 1) d 4 = a + ( n − 1)2 4 = a + 2 n − 2 a + 2 n = 6 a = 6 − 2 n (i) S n = n 2 [ a + a n] - 14 = n 2 [ a + 4] −28 = n ( a + 4) −28 = n (6 − 2 n … dated image